Difference between revisions of "Team:Aix-Marseille/Design"

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<section style="padding:30px 0px 30px;background-color: #FBF1FB;" "background:#fbf1fb;"="" class="bg-2 arrow_box2;">     
 
<section style="padding:30px 0px 30px;background-color: #FBF1FB;" "background:#fbf1fb;"="" class="bg-2 arrow_box2;">     
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     <h2 class="title wow bounce in up"><span style ="color:#000000"><span style="font-family:Armalite Rifle">Our strategy</span></span></h2>
 
     <h2 class="title wow bounce in up"><span style ="color:#000000"><span style="font-family:Armalite Rifle">Our strategy</span></span></h2>
 
     <div class="space30"></div>
 
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     <p class="space20"><div align="justify"><span style ="color:#000000"><span style="font-family:Courier New">Our strategy is to use a <b>reduced laccase</b> which will be oxidized by the oxygen present in the air. </p></span></div> </span>
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     <p class="space20"><div align="justify"><span style="font-family:Courier New"><span style ="color:#000000">Our strategy is to use a reduced laccase which will be oxidized by the oxygen present in the air.</p></span></span>
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<p class="space10"><div align="justify"><span style ="color:#000000"><span style="font-family:Courier New">To return at a reduced state, laccase will <b>oxidize the cytochrom C</b> previously excited by light.
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<p><span style="font-family:Courier New"><span style ="color:#000000">To return at a reduced state, laccase will oxidize the cytochrom C previously excited by light.</p></span></span>
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<p class="space10"><div align="justify"><span style ="color:#000000"><span style="font-family:Courier New">When the cytochrome C will come back to its reduced state, the polymers will be in a radical state. </p></span></div></span>
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<p><span style="font-family:Courier New"><span style ="color:#000000">When the cytochrome C will come back to its reduced state, the polymers will be in a radical state.</p></span></span>
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<p class="space10"><div align="justify"><span style ="color:#000000"><span style="font-family:Courier New">Thanks to oxygen, it will form an epoxide that will be hydrolyzed and become a <b>diol</b>. </p></span></div></span>
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<p><span style="font-family:Courier New"><span style ="color:#000000">Thanks to oxygen, it will form an epoxide that will be hydrolyzed and become a diol.</p></span></span>
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<p class="space10"><div align="justify"><span style ="color:#000000"><span style="font-family:Courier New">So we think that the polymer degradation will be more efficient by this method.  
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<p><span style="font-family:Courier New"><span style ="color:#000000">So we think that the polymer degradation will be more efficient by this method.  
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     <h2 class="title wow bounce in up"><span style ="color:#000000"><span style="font-family:Armalite Rifle">Production</span></span></h2>
 
     <h2 class="title wow bounce in up"><span style ="color:#000000"><span style="font-family:Armalite Rifle">Production</span></span></h2>
 
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     <p class="space20"><div align="justify"><span style ="color:#000000"><span style="font-family:Courier New">Once our constructions done, we transform its into BL21 cells.  
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     <p><div align="justify"><span style ="color:#000000"><span style="font-family:Courier New">Once our constructions done, we transform its into BL21 cells.  
 
These E.coli K-12 allow the expression of proteins controlled by the T7 promotor and induced by IPTG.  
 
These E.coli K-12 allow the expression of proteins controlled by the T7 promotor and induced by IPTG.  
 
Bacteria cells were resuspended into a lysis buffer and were sonicated. Sonication of bacteria is used to break cells that contain our proteins to be purified. After, a centrifugation separates broken/unbroken cells and allows us to collect soluble proteins into the supernatant.  
 
Bacteria cells were resuspended into a lysis buffer and were sonicated. Sonication of bacteria is used to break cells that contain our proteins to be purified. After, a centrifugation separates broken/unbroken cells and allows us to collect soluble proteins into the supernatant.  

Revision as of 09:16, 15 September 2015

Chew fight

Project design

Our project this year is to work on the chewing gum degradation. Our research on this topic reveals that chewing gum is composed of different compounds. They are hydrophilic or hydrophobic. When you chew a chewing gum, the hydrophilic part is solubilized by your saliva. Once done, you throw away the hydrophobic part called the gum base. The gum base is composed of polymers : polyisoprene and butadiene.

So we searched for enzymes which are able to degrade polymers. We found two enzymes: lipoxygenases and laccases.

At the beginning, our main problem was that laccase is able to oxidize the ruthenium. But we did not want to use it in our project because of its scarcity, its toxicity and impact on the environment. We found that the cytochrome C which uses iron could replace it and be oxidized by laccases. We decided to try and asked if it could help to degrade our polymers. We selected several enzymes that we believed could be great to use in E.coli strain.

Our strategy

Our strategy is to use a reduced laccase which will be oxidized by the oxygen present in the air.

To return at a reduced state, laccase will oxidize the cytochrom C previously excited by light.

When the cytochrome C will come back to its reduced state, the polymers will be in a radical state.

Thanks to oxygen, it will form an epoxide that will be hydrolyzed and become a diol.

So we think that the polymer degradation will be more efficient by this method.