(We helped Shenzhen_SFLS with part of their modeling, and there're the results)
We have acknowledged that one Ab with wAg + one Ag coming into one Ab with Ag and one wAg is irreversible and the amount of this kind of changes is related to the amount of Ab with wAg(x2) , the amount of Ag (x1) and time.
According to Volterra Model,we can know that ‘dx1/dt=dx2/dt=-k*x1*x2’.
k is a regular value which is related to affinity(f) between one Ab with wAg and one Ag which is defined as p,so we can attain an another equation:’k=pf’.
According to the first equation above,we can know that ‘x2=x1+m’.
We assume that the inchoate value of x1 is x0.
Difference between revisions of "Team:SZMS 15 Shenzhen/Collaborations"
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<li class="nav-li"><a href="https://2015.igem.org/Team:SZMS_15_Shenzhen/project">Project</a></li> | <li class="nav-li"><a href="https://2015.igem.org/Team:SZMS_15_Shenzhen/project">Project</a></li> | ||
<li class="nav-li"><a href="https://2015.igem.org/Team:SZMS_15_Shenzhen/interlab">Interlab</a></li> | <li class="nav-li"><a href="https://2015.igem.org/Team:SZMS_15_Shenzhen/interlab">Interlab</a></li> | ||
| + | <li class="nav-li"><a href="https://2015.igem.org/Team:SZMS_15_Shenzhen/Practices">Practice</a></li> | ||
<li class="nav-li"><a href="https://2015.igem.org/Team:SZMS_15_Shenzhen/gallery">Gallery</a></li> | <li class="nav-li"><a href="https://2015.igem.org/Team:SZMS_15_Shenzhen/gallery">Gallery</a></li> | ||
<li class="nav-li"><a href="https://2015.igem.org/Team:SZMS_15_Shenzhen/teamintro">About us</a></li> | <li class="nav-li"><a href="https://2015.igem.org/Team:SZMS_15_Shenzhen/teamintro">About us</a></li> | ||
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<div class="heading"> | <div class="heading"> | ||
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<div class="heading-text-title">Collabotations</div> | <div class="heading-text-title">Collabotations</div> | ||
| − | <div class="heading-text-content"> We have acknowledged that one Ab with wAg + one Ag coming into one Ab with Ag and one wAg is irreversible and the amount of this kind of changes is related to the amount of Ab with wAg(x2) , the amount of Ag (x1) and time. | + | <div class="heading-text-content">(We helped Shenzhen_SFLS with part of their modeling, and there're the results)<br><br> |
| − | < | + | We have acknowledged that one Ab with wAg + one Ag coming into one Ab with Ag and one wAg is irreversible and the amount of this kind of changes is related to the amount of Ab with wAg(x2) , the amount of Ag (x1) and time.<br><br> |
| − | + | According to Volterra Model,we can know that ‘dx1/dt=dx2/dt=-k*x1*x2’. | |
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<br><br> | <br><br> | ||
| − | k is a regular value which is related to affinity(f) between one Ab with wAg and one Ag which is defined as p,so we can attain an another equation:’k=pf’. | + | k is a regular value which is related to affinity(f) between one Ab with wAg and one Ag which is defined as p,so we can attain an another equation:’k=pf’.<br><br>According to the first equation above,we can know that ‘x2=x1+m’.<br><br> |
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We assume that the inchoate value of x1 is x0. | We assume that the inchoate value of x1 is x0. | ||
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| − | <div class=" | + | <div class="heading-text-content">‘dx1/dt=dx2/dt=-k*x1*x2’<br><br> |
’k=pf’<br><br> | ’k=pf’<br><br> | ||
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‘E=(x0-x1)/x1’ which is simplified as ‘E=1- m/((exp(m*(log((m + x0)/x0)/m + f*p*t)) - 1)*x0)’ | ‘E=(x0-x1)/x1’ which is simplified as ‘E=1- m/((exp(m*(log((m + x0)/x0)/m + f*p*t)) - 1)*x0)’ | ||
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<font class="buttom-intro" color="#555555">Collaborations Team:SZMS_15_Shenzhen</font> | <font class="buttom-intro" color="#555555">Collaborations Team:SZMS_15_Shenzhen</font> | ||
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Latest revision as of 09:36, 18 September 2015
Collabotations
‘dx1/dt=dx2/dt=-k*x1*x2’
’k=pf’
‘x2=x1+m’
‘x1(0)=x0’
And the program code of matlab is:
dsolve('Dx1=-p*f*x1*(x1+m)','x1(0)=x0','t')
ans =
m/(exp(m*(log((m + x0)/x0)/m + f*p*t)) - 1)
x1= m/(exp(m*(log((m + x0)/x0)/m + f*p*t)) - 1)
We can define the extend of combination as E.
‘E=(x0-x1)/x1’ which is simplified as ‘E=1- m/((exp(m*(log((m + x0)/x0)/m + f*p*t)) - 1)*x0)’
’k=pf’
‘x2=x1+m’
‘x1(0)=x0’
And the program code of matlab is:
dsolve('Dx1=-p*f*x1*(x1+m)','x1(0)=x0','t')
ans =
m/(exp(m*(log((m + x0)/x0)/m + f*p*t)) - 1)
x1= m/(exp(m*(log((m + x0)/x0)/m + f*p*t)) - 1)
We can define the extend of combination as E.
‘E=(x0-x1)/x1’ which is simplified as ‘E=1- m/((exp(m*(log((m + x0)/x0)/m + f*p*t)) - 1)*x0)’