Difference between revisions of "Team:Aix-Marseille/Design"

Line 175: Line 175:
 
     <div class="space30"></div>
 
     <div class="space30"></div>
 
     <p class="space20"><div align="justify"><span style ="color:#000000"><span style="font-family:Courier New">Our strategy is to use a <b>reduced laccase</b> which will be oxidized by the oxygen present in the air. </p></span></div> </span>
 
     <p class="space20"><div align="justify"><span style ="color:#000000"><span style="font-family:Courier New">Our strategy is to use a <b>reduced laccase</b> which will be oxidized by the oxygen present in the air. </p></span></div> </span>
−
<p class="space10"><div align="justify"><span style ="color:#000000"><span style="font-family:Courier New">To return at a reduced state, laccase will <b>oxidize the cytochrom C</b> previously excited by light. A <b>superoxide anion radical</b> will be formed.  </p></span></div></span>
+
<p class="space10"><div align="justify"><span style ="color:#000000"><span style="font-family:Courier New">To return at a reduced state, laccase will <b>oxidize the cytochrom C</b> previously excited by light.
−
<p class="space10"><div align="justify"><span style ="color:#000000"><span style="font-family:Courier New">When the cytochrome C will come back to its reduced state and the superoxide anion radical to oxygen, the polymers will be in a radical state. </p></span></div></span>
+
<p class="space10"><div align="justify"><span style ="color:#000000"><span style="font-family:Courier New">When the cytochrome C will come back to its reduced state, the polymers will be in a radical state. </p></span></div></span>
 
<p class="space10"><div align="justify"><span style ="color:#000000"><span style="font-family:Courier New">Thanks to oxygen, it will form an epoxide that will be hydrolyzed and become a <b>diol</b>.  </p></span></div></span>
 
<p class="space10"><div align="justify"><span style ="color:#000000"><span style="font-family:Courier New">Thanks to oxygen, it will form an epoxide that will be hydrolyzed and become a <b>diol</b>.  </p></span></div></span>
 
<p class="space10"><div align="justify"><span style ="color:#000000"><span style="font-family:Courier New">So we think that the polymer degradation will be more efficient by this method.  
 
<p class="space10"><div align="justify"><span style ="color:#000000"><span style="font-family:Courier New">So we think that the polymer degradation will be more efficient by this method.  
Line 185: Line 185:
 
     <div class="col-md-5 col-md-offset-1  col-sm-offset-1  space30">
 
     <div class="col-md-5 col-md-offset-1  col-sm-offset-1  space30">
 
                    
 
                    
−
                             <img src=http://i.imgur.com/ALW2dJd.png" class="img-responsive" width="500" height="500">
+
                             <img src=http://i.imgur.com/ALW2dJd.png" class="img-responsive">
 
    
 
    
 
                         </div>
 
                         </div>

Revision as of 09:03, 15 September 2015

Chew fight

Project design

Our project this year is to work on the chewing gum degradation. Our research on this topic reveals that chewing gum is composed of different compounds. They are hydrophilic or hydrophobic. When you chew a chewing gum, the hydrophilic part is solubilized by your saliva. Once done, you throw away the hydrophobic part called the gum base. The gum base is composed of polymers : polyisoprene and butadiene.

So we searched for enzymes which are able to degrade polymers. We found two enzymes: lipoxygenases and laccases.

At the beginning, our main problem was that laccase is able to oxidize the ruthenium. But we did not want to use it in our project because of its scarcity, its toxicity and impact on the environment. We found that the cytochrome C which uses iron could replace it and be oxidized by laccases. We decided to try and asked if it could help to degrade our polymers. We selected several enzymes that we believed could be great to use in E.coli strain.

Our strategy

Our strategy is to use a reduced laccase which will be oxidized by the oxygen present in the air.

To return at a reduced state, laccase will oxidize the cytochrom C previously excited by light.

When the cytochrome C will come back to its reduced state, the polymers will be in a radical state.

Thanks to oxygen, it will form an epoxide that will be hydrolyzed and become a diol.

So we think that the polymer degradation will be more efficient by this method.