Difference between revisions of "Team:Dundee/Modeling"
Fmacfarlane (Talk | contribs) |
Fmacfarlane (Talk | contribs) |
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$$ \begin{equation*} \frac{dm}{dt} = k_T - k_D \cdot m \end{equation*}$$ | $$ \begin{equation*} \frac{dm}{dt} = k_T - k_D \cdot m \end{equation*}$$ | ||
$$ \frac{dP}{dt} = \alpha \cdot m - \beta \cdot P $$ | $$ \frac{dP}{dt} = \alpha \cdot m - \beta \cdot P $$ | ||
+ | |||
+ | $\ce{HCl}$ dissociates in water as follows: | ||
+ | $$\ce{H2O + HCl<=>H3O+ + Cl-}$$ | ||
total amount of haptoglobin, \( HpT \), will be equal to | total amount of haptoglobin, \( HpT \), will be equal to |
Revision as of 14:03, 10 July 2015
Modeling
The modeling part. Example:
$$ \begin{equation*} \frac{dm}{dt} = k_T - k_D \cdot m \end{equation*}$$ $$ \frac{dP}{dt} = \alpha \cdot m - \beta \cdot P $$ $\ce{HCl}$ dissociates in water as follows: $$\ce{H2O + HCl<=>H3O+ + Cl-}$$ total amount of haptoglobin, \( HpT \), will be equal to
The modeling part. Example:
$$ \begin{equation*} \frac{dm}{dt} = k_T - k_D \cdot m \end{equation*}$$ $$ \frac{dP}{dt} = \alpha \cdot m - \beta \cdot P $$ $\ce{HCl}$ dissociates in water as follows: $$\ce{H2O + HCl<=>H3O+ + Cl-}$$ total amount of haptoglobin, \( HpT \), will be equal to
Under construction