Difference between revisions of "Team:HokkaidoU Japan/Modeling"

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<h1>Modeling</h1>
 
<h1>Modeling</h1>
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<br><br>Conclusion
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1. Toxicity of thanatin
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We conducted MIC test to assay thanatin’s activity and we found that thanatin has high toxicity and minimum inhibitory concentration lies between 0.6 and 1.2 µM (1).
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  It’s known that minimum inhibitory concentration of Wild Type thanatin lies between 0.6 and 1.2 µM (1) and OD610 of E.coli expressing Wild Type thanatin reach to 0.3 at most as below.
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    Compared with this fact, thanatin fused with Ag43 has less activity and the maximum OD600 of 2mer thanatin fused Ag43 is 1.5
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    Thus, we concluded that we succeeded inactivation of thanatin by maltimerization and fusing with Ag43.
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2. Effect of thanatin multimerization
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Fig.10 shows that as the number of thanatin-repeat increases growth of E.coli is more inhibited. There are three
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3. Possibility in monomerization of Thanatin by AspN
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<P>Here, we would like to think the following system as a mathmatical model;
 
<P>Here, we would like to think the following system as a mathmatical model;

Revision as of 11:18, 18 September 2015

main2

Microbusters

Modeling



Conclusion 1. Toxicity of thanatin We conducted MIC test to assay thanatin’s activity and we found that thanatin has high toxicity and minimum inhibitory concentration lies between 0.6 and 1.2 µM (1). It’s known that minimum inhibitory concentration of Wild Type thanatin lies between 0.6 and 1.2 µM (1) and OD610 of E.coli expressing Wild Type thanatin reach to 0.3 at most as below. Compared with this fact, thanatin fused with Ag43 has less activity and the maximum OD600 of 2mer thanatin fused Ag43 is 1.5 Thus, we concluded that we succeeded inactivation of thanatin by maltimerization and fusing with Ag43. 2. Effect of thanatin multimerization Fig.10 shows that as the number of thanatin-repeat increases growth of E.coli is more inhibited. There are three 3. Possibility in monomerization of Thanatin by AspN


Here, we would like to think the following system as a mathmatical model;

  1. E. coli can produce Ag43 replacing α-domain with His-tag recombinant antimicrobial peptides
  2. The antimicrobial peptide constitutively can be secreted through Ag43 system. There are large amount of AspN in liquid culture and the peptides diffuse and outflow in the culture rapidly
  3. We can purify antimicrobial peptides with His-tag affinity column
We want to

If amount of antimicrobial peptides (here referred to as A) bacteria cell produce is increased, conversely the number of host cells (referred to as N) will be decreased because of toxicity of the peptide. We want to express this relation as a mathmatical model. First, we want to describe the number of host cells growing without toxicity of the peptide as the differential equation. The logistic equation is a model of population growth first published by Pierre Verhulst. The logistic model is described by the following differential equation

This is a logistic curve

where a is rate of maximum population growth and K is carrying capacity and defining b=a/K then gives the differential equation. Next, we add the term of toxicity of the antimicrobial peptide to this equation and we describe amount of antimicrobial peptides in the second differential equation as follow.

This is differential equations
This is a differential equations

where c is rate of toxicity of the antimicrobial peptide, e is rate of expression of the antimicrobial peptide f is rate of decomposition of the antimicrobial peptide We took 1 for 3 constants (a, b, c) of the right side in the first formula using the flexibilities of the scale (In scale transformation, e, f will change into α, β) Here, we change parameters α and β values arbitrarily and find these graph below(Figure.1).

This is a graph

Figure1. Population of bacteria expressing the antimicrobial peptide at various value of α and β

We can expect that the amount of antimicrobial peptides and population of bacteria will be constant at last regardless of parameter α and β value. So, we would like to make sure the fixed points of these differential equations is stable or not. Let each of differential equations equal to zero, and solve them then we can get the fixed points of these equations

This is ///

Define N≡X,A≡Y and minute intervals as (δx, δy). the right side in both differential equations as follow.

This is ///
This is ///

Determine the value of eigenvalues of each matrixes and if two eigenvalues are negative, we can find the fixed point stable, if positive we can find the fixed point instable.

The result of calculation is
This is a graph
This is a graph

Therefore, we illustrated that amount of AMP and population of bacteria will be constant at last regardless of parameter α and β value.

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