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− | <p> 3) Water Treatment
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− | <p>Theoretically Power of Turbine:
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− | <center> Pth = ρ q g h </center>
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− | <p>The theoretically power available from a flow of 1m^3/s water falling 100m:</p>
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− | <p> Pth = (1000kg/m^3) (1m^3/s)(9.81ms^-2)(100m) </p>
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− | = 981 kw </p>
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− | <p>Since the work done is equal to the power flow through 100m in 1s.</p>
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− | <center> P=W/t </center>
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− | <p> Therefore, W=981 kJ </p>
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− | <p>After that, we would like to calculate the force created by the water flow. Since the work done is equal to the multiple of force and displacement that the water flow through.</p>
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− | <center> W=Fs </center>
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− | <p> Therefore, the force act on each magnetosome is </p>
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− | F= 981000/100=9810 N
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− | A straight wire electromagnet is needed to use to hold the magnetosome tightly with a strong magnetic force. The magnetic force produced by the electromagnet Fm is equal or bigger to the force created by the water flow Fwf since we need to hold the magnetosome tightly.
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− | Fm=Fwf
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− | Assume that the electromagnet with 1000 turns of wires and operate with 10A of current 1.5 meters from a piece of metal,
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− | Force = ((N x I)^2 x k x A) / (2 x g^2)
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− | The cross-sectional area of the electromagnet = 351 meters-square.
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