Difference between revisions of "Team:Paris Bettencourt/Modeling"

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<p>
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When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are
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$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$
 
$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$
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</p>
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Revision as of 15:12, 13 August 2015