Difference between revisions of "Team:Heidelberg/Modelling/aptakinetics"

Line 96: Line 96:
 
     <td>\[
 
     <td>\[
 
         \frac{d[A]}{dt}=-k_{syn}[A][T_{act}]
 
         \frac{d[A]}{dt}=-k_{syn}[A][T_{act}]
 +
        \]
 +
    </td>
 +
</tr>
 +
<tr>
 +
    <td rowspan="4">$M$</td>
 +
    <td>Basic model<br/>Variant 2</td>
 +
    <td>\[
 +
        \frac{d[M]}{dt}=\frac{k_{syn}}{n_{A}}[A][T_{act}]
 +
        \]
 +
    </td>
 +
</tr>
 +
<tr>
 +
    <td>Variant 1</td>
 +
    <td>\[
 +
        \frac{d[M]}{dt}=\frac{k_{syn}}{n_{A}}\frac{[A][T_{act}]}{K_{m,T}+[T_{act}]}
 +
        \]
 +
    </td>
 +
<tr>
 +
    <td>Variant 3</td>
 +
    <td>\[
 +
        \frac{d[M]}{dt}=\frac{k_{syn}}{n_{A,0}\frac{[A]^{k}}{[T_{act}]^{l}}}[A][T_{act}]=\frac{k_{syn}}{n_{A,0}}[A]^{1-k}[T_{act}]^{1+j}
 +
        \]
 +
    </td>
 +
</tr>
 +
<tr>
 +
    <td>Variants 4, 4a, 4b, 4c</td>
 +
    <td>\[
 +
        \frac{d[M]}{dt}=\frac{k_{syn}}{n_{A,0}\frac{[A]}{[T_{act}]^{l}}}[A][T_{act}]=\frac{k_{syn}}{n_{A,0}}[T_{act}]^{1+j}
 
         \]
 
         \]
 
     </td>
 
     </td>

Revision as of 20:13, 18 September 2015

Model species Variant Equation
$P$ Basic model
Variants 1 to 4, 4c
\[ \frac{d[P]}{dt}=-k_{on}[T][P]+k_{off}[T_{act}]-k_{deg,P}[P] \]
Variant 4a \[ [P](t)=[P](t_{0})\exp\left(-k_{deg,P}t\right) \]
Variant 4b \[ \frac{d[P]}{dt}=-k_{on}[T][P]+k_{off}[T_{act}] \]
$T$ Basic model
Variants 1 to 4, 4b, 4c
\[ \frac{d[T]}{dt}=-k_{on}[T][P]+k_{off}[T_{act}] \]
Variant 4a \[ [T]=[T_{tot}]-[T_{act}] \]
$T_{act}$ Basic model
Variants 1 to 4, 4b, 4c
\[ \frac{d[T_{act}]}{dt}=k_{on}[T][P]-k_{off}[T_{act}] \]
Variant 4a \[ [T_{act}]=\frac{[T_{tot}][P]}{K_{d,P}} \]
$A$ Basic model
Variants 2 to 4, 4a, 4b
\[ \frac{d[A]}{dt}=-k_{syn}[A][T_{act}]-k_{deg,A}[A] \]
Variant 1 \[ \frac{d[A]}{dt}=-k_{syn}\frac{[A][T_{act}]}{K_{m,T}+[T_{act}]}-k_{deg,A}[A] \]
Variant 4c \[ \frac{d[A]}{dt}=-k_{syn}[A][T_{act}] \]
$M$ Basic model
Variant 2
\[ \frac{d[M]}{dt}=\frac{k_{syn}}{n_{A}}[A][T_{act}] \]
Variant 1 \[ \frac{d[M]}{dt}=\frac{k_{syn}}{n_{A}}\frac{[A][T_{act}]}{K_{m,T}+[T_{act}]} \]
Variant 3 \[ \frac{d[M]}{dt}=\frac{k_{syn}}{n_{A,0}\frac{[A]^{k}}{[T_{act}]^{l}}}[A][T_{act}]=\frac{k_{syn}}{n_{A,0}}[A]^{1-k}[T_{act}]^{1+j} \]
Variants 4, 4a, 4b, 4c \[ \frac{d[M]}{dt}=\frac{k_{syn}}{n_{A,0}\frac{[A]}{[T_{act}]^{l}}}[A][T_{act}]=\frac{k_{syn}}{n_{A,0}}[T_{act}]^{1+j} \]