Difference between revisions of "Team:Cambridge-JIC/Measurement"
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<h3>Theory of Optics</h3> | <h3>Theory of Optics</h3> | ||
<p> The resolution can be limited by two independent factors: </p> <ul><li><p>pixel size;</p></li><li><p>diffraction effects.</p></li></ul> | <p> The resolution can be limited by two independent factors: </p> <ul><li><p>pixel size;</p></li><li><p>diffraction effects.</p></li></ul> | ||
− | <div style="float:left"> <img src="//2015.igem.org/wiki/images/8/8b/CamJIC-Resolution.jpg" style="height: | + | <div style="float:left"> <img src="//2015.igem.org/wiki/images/8/8b/CamJIC-Resolution.jpg" style="height:250px;margin:20px"> </div> <p> The larger of these determines the actual limitation of the system. In our case we know that the pixel size is 1.4 μm, so we now need to work out the diffraction limit, that is the smallest spot size which can be produced by the lens with the given specs. To calculate this, recall the Rayleigh criterion for a circular aperture: |
sinθ=1.22 λ/d. Here λ~550nm is the wavelength of light, taking green for the middle of the visible spectrum, d=1.25mm is the diameter of the aperture and θ (small angle) is the angular radius of the spot, that is tanθ=r/L. Here r is the radius of the spot projected at a distance L from the aperture, which in our setup is actually the focal length f of the Raspberry Pi camera lens (and the spot is projected onto the CCD sensor). | sinθ=1.22 λ/d. Here λ~550nm is the wavelength of light, taking green for the middle of the visible spectrum, d=1.25mm is the diameter of the aperture and θ (small angle) is the angular radius of the spot, that is tanθ=r/L. Here r is the radius of the spot projected at a distance L from the aperture, which in our setup is actually the focal length f of the Raspberry Pi camera lens (and the spot is projected onto the CCD sensor). | ||
From first approximation for a small angle: sinθ≈tanθ, so 1.22 λ/d=r/f. Rearranging this equation and plugging in the numbers gives the following diameter of the smallest resolvable spot: 2r≈3.8μm. This is almost three times the size of the pixel on the CCD, which imposes the actual limit on the resolution. The pixels of the CCD outresolve the theoretical lens limits.</p> | From first approximation for a small angle: sinθ≈tanθ, so 1.22 λ/d=r/f. Rearranging this equation and plugging in the numbers gives the following diameter of the smallest resolvable spot: 2r≈3.8μm. This is almost three times the size of the pixel on the CCD, which imposes the actual limit on the resolution. The pixels of the CCD outresolve the theoretical lens limits.</p> |
Revision as of 13:06, 30 July 2015